AP Physics 1 MCQ Practice by Topic 2027
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Newton’s Second Law Practice
All questions are original. Check each answer for immediate feedback and explanation, then use the lesson link inside the explanation when a concept needs repair.
A 2 kg cart experiences a net force of 12 N to the right. What is its acceleration?
Correct answer: A. Newton’s second law gives a = F_net/m = 6 m/s².
A 3 kg cart experiences a net force of 18 N to the right. What is its acceleration?
Correct answer: A. Newton’s second law gives a = F_net/m = 6 m/s².
A 4 kg cart experiences a net force of 24 N to the right. What is its acceleration?
Correct answer: A. Newton’s second law gives a = F_net/m = 6 m/s².
A 5 kg cart experiences a net force of 30 N to the right. What is its acceleration?
Correct answer: A. Newton’s second law gives a = F_net/m = 6 m/s².
A 6 kg cart experiences a net force of 36 N to the right. What is its acceleration?
Correct answer: A. Newton’s second law gives a = F_net/m = 6 m/s².
A 7 kg cart experiences a net force of 42 N to the right. What is its acceleration?
Correct answer: A. Newton’s second law gives a = F_net/m = 6 m/s².
The same net force of 12 N acts separately on a 2 kg cart and a 4 kg cart. How do their accelerations compare?
Correct answer: A. For fixed net force, acceleration is inversely proportional to mass.
The same net force of 16 N acts separately on a 2 kg cart and a 4 kg cart. How do their accelerations compare?
Correct answer: A. For fixed net force, acceleration is inversely proportional to mass.
The same net force of 20 N acts separately on a 2 kg cart and a 4 kg cart. How do their accelerations compare?
Correct answer: A. For fixed net force, acceleration is inversely proportional to mass.
The same net force of 24 N acts separately on a 2 kg cart and a 4 kg cart. How do their accelerations compare?
Correct answer: A. For fixed net force, acceleration is inversely proportional to mass.
The same net force of 28 N acts separately on a 2 kg cart and a 4 kg cart. How do their accelerations compare?
Correct answer: A. For fixed net force, acceleration is inversely proportional to mass.
The same net force of 32 N acts separately on a 2 kg cart and a 4 kg cart. How do their accelerations compare?
Correct answer: A. For fixed net force, acceleration is inversely proportional to mass.
A car moves right at 10 m/s but has a net force of 1000 N to the left. What does Newton’s second law guarantee?
Correct answer: A. Acceleration is in the direction of the net force. It can oppose the current velocity while the car slows.
A car moves right at 12 m/s but has a net force of 1200 N to the left. What does Newton’s second law guarantee?
Correct answer: A. Acceleration is in the direction of the net force. It can oppose the current velocity while the car slows.
A car moves right at 14 m/s but has a net force of 1400 N to the left. What does Newton’s second law guarantee?
Correct answer: A. Acceleration is in the direction of the net force. It can oppose the current velocity while the car slows.
A car moves right at 16 m/s but has a net force of 1600 N to the left. What does Newton’s second law guarantee?
Correct answer: A. Acceleration is in the direction of the net force. It can oppose the current velocity while the car slows.
A car moves right at 18 m/s but has a net force of 1800 N to the left. What does Newton’s second law guarantee?
Correct answer: A. Acceleration is in the direction of the net force. It can oppose the current velocity while the car slows.
A car moves right at 20 m/s but has a net force of 2000 N to the left. What does Newton’s second law guarantee?
Correct answer: A. Acceleration is in the direction of the net force. It can oppose the current velocity while the car slows.
A 4 kg block has 20 N right and 8 N left. What is its horizontal acceleration?
Correct answer: A. First find the signed net force, then divide by mass.
A 4 kg block has 22 N right and 9 N left. What is its horizontal acceleration?
Correct answer: A. First find the signed net force, then divide by mass.
A 4 kg block has 24 N right and 10 N left. What is its horizontal acceleration?
Correct answer: A. First find the signed net force, then divide by mass.
A 4 kg block has 26 N right and 11 N left. What is its horizontal acceleration?
Correct answer: A. First find the signed net force, then divide by mass.
A 4 kg block has 28 N right and 12 N left. What is its horizontal acceleration?
Correct answer: A. First find the signed net force, then divide by mass.
A 4 kg block has 30 N right and 13 N left. What is its horizontal acceleration?
Correct answer: A. First find the signed net force, then divide by mass.
A 40 kg rider in an elevator accelerates upward at 2 m/s². Take g = 10 m/s². What normal force does the scale exert?
Correct answer: A. Choose upward positive: N − mg = ma, so N = m(g+a).
A 45 kg rider in an elevator accelerates upward at 2 m/s². Take g = 10 m/s². What normal force does the scale exert?
Correct answer: A. Choose upward positive: N − mg = ma, so N = m(g+a).
A 50 kg rider in an elevator accelerates upward at 2 m/s². Take g = 10 m/s². What normal force does the scale exert?
Correct answer: A. Choose upward positive: N − mg = ma, so N = m(g+a).
A 55 kg rider in an elevator accelerates upward at 2 m/s². Take g = 10 m/s². What normal force does the scale exert?
Correct answer: A. Choose upward positive: N − mg = ma, so N = m(g+a).
A 60 kg rider in an elevator accelerates upward at 2 m/s². Take g = 10 m/s². What normal force does the scale exert?
Correct answer: A. Choose upward positive: N − mg = ma, so N = m(g+a).
A 65 kg rider in an elevator accelerates upward at 2 m/s². Take g = 10 m/s². What normal force does the scale exert?
Correct answer: A. Choose upward positive: N − mg = ma, so N = m(g+a).
A block accelerates down a frictionless 15° incline. Which component equation is most useful if the x-axis is chosen down the incline?
Correct answer: A. Aligning an axis with the acceleration simplifies the component equation; gravity contributes mg sinθ along the incline.
A block accelerates down a frictionless 20° incline. Which component equation is most useful if the x-axis is chosen down the incline?
Correct answer: A. Aligning an axis with the acceleration simplifies the component equation; gravity contributes mg sinθ along the incline.
A block accelerates down a frictionless 25° incline. Which component equation is most useful if the x-axis is chosen down the incline?
Correct answer: A. Aligning an axis with the acceleration simplifies the component equation; gravity contributes mg sinθ along the incline.
A block accelerates down a frictionless 30° incline. Which component equation is most useful if the x-axis is chosen down the incline?
Correct answer: A. Aligning an axis with the acceleration simplifies the component equation; gravity contributes mg sinθ along the incline.
A block accelerates down a frictionless 35° incline. Which component equation is most useful if the x-axis is chosen down the incline?
Correct answer: A. Aligning an axis with the acceleration simplifies the component equation; gravity contributes mg sinθ along the incline.
A block accelerates down a frictionless 40° incline. Which component equation is most useful if the x-axis is chosen down the incline?
Correct answer: A. Aligning an axis with the acceleration simplifies the component equation; gravity contributes mg sinθ along the incline.
A 1 kg block and a 2 kg block connected by an ideal string accelerate together on a horizontal surface. What is a useful first system choice for finding their common acceleration?
Correct answer: A. Choosing the two blocks as one system removes internal tension from the net external-force equation.
A 2 kg block and a 3 kg block connected by an ideal string accelerate together on a horizontal surface. What is a useful first system choice for finding their common acceleration?
Correct answer: A. Choosing the two blocks as one system removes internal tension from the net external-force equation.
A 3 kg block and a 4 kg block connected by an ideal string accelerate together on a horizontal surface. What is a useful first system choice for finding their common acceleration?
Correct answer: A. Choosing the two blocks as one system removes internal tension from the net external-force equation.
A 4 kg block and a 5 kg block connected by an ideal string accelerate together on a horizontal surface. What is a useful first system choice for finding their common acceleration?
Correct answer: A. Choosing the two blocks as one system removes internal tension from the net external-force equation.
A 5 kg block and a 6 kg block connected by an ideal string accelerate together on a horizontal surface. What is a useful first system choice for finding their common acceleration?
Correct answer: A. Choosing the two blocks as one system removes internal tension from the net external-force equation.
A 6 kg block and a 7 kg block connected by an ideal string accelerate together on a horizontal surface. What is a useful first system choice for finding their common acceleration?
Correct answer: A. Choosing the two blocks as one system removes internal tension from the net external-force equation.