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Academic Support AP Statistics Unit 3: Inference for Categorical Data: Proportions

Chi-Square Test of Independence: Complete Guide

Learn chi square test of independence with current AP Statistics scope, proper formulas, worked examples, and original Easy, Tough, and Toughest questions.

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Statistical Procedure

Chi-Square Test of Independence: Complete Guide

A decision-and-workflow guide for a chi-square test of independence, covering method selection, conditions, mathematics, calculator evidence, and contextual reporting.

Course status: Revised 2026-27 course
Updated: July 18, 2026
Practice: Easy, Tough and Toughest

Method at a Glance: Chi-Square Test Of Independence

A chi-square test of independence uses one population classified by two categorical variables and concludes about association between those variables.

Reader taskone population, two categorical variables, expected counts, df, and association
Planned modules8
Mathematics2 expressions
Worked checks45

Boundary: The conclusion concerns association within one population.

Procedure Workflow

  1. Identify the data structure and parameter before selecting chi square test of independence; the name of a calculator menu is not method evidence.
  2. State the hypotheses or estimation target for chi square test of independence using population notation and the order defined by the question.
  3. Verify the design, independence, and approximation conditions that specifically justify chi square test of independence rather than reciting every condition learned in the course.
  4. Compute the statistic, standard error, interval, or p-value for chi square test of independence with defined symbols, guard digits, and an independent arithmetic check.
  5. Interpret chi square test of independence in the population and units named by the problem, then limit causation and generalization to what the collection design supports.

Procedure Formulas and Notation

Expected cell count

Eij=(row i total)(column j total)n

Expected cell count in Chi-Square Test Of Independence: Compute expected counts from the null model, then retain each cell contribution before summing so the result can be audited.

Chi-square degrees of freedom

df=(r1)(c1)

Chi-square degrees of freedom in Chi-Square Test Of Independence: This expression belongs specifically to a chi-square test of independence; define every symbol and apply the scope rule for one population, two categorical variables, expected counts, df, and association before calculation.

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Step 1

Two-way table

Decision

For Two-way table in chi square test of independence, One constructed random sample from a tutoring-program evaluation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 27, 15]. Test independence for two-way table.

Two-way table result in chi square test of independence: For the independence test, χ2=5.043, df=2, and p=0.0804; expected counts model no association within the population.

Eij=(row totali)(column totalj)120,χ2=5.043,df=2.

Interpretation and validity

Two-way table interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Two-way table: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 2

Hypotheses

Decision

For Hypotheses in chi square test of independence, One constructed random sample from a school library checkout study classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 28, 15]. Test independence for hypotheses.

Hypotheses result in chi square test of independence: For the independence test, χ2=5.782, df=2, and p=0.0555; expected counts model no association within the population.

Eij=(row totali)(column totalj)122,χ2=5.782,df=2.

Interpretation and validity

Hypotheses interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Hypotheses: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 3

Expected counts

Decision

For Expected counts in chi square test of independence, One constructed random sample from a package-delivery sample classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 29, 15]. Test independence for expected counts.

Expected counts result in chi square test of independence: For the independence test, χ2=6.573, df=2, and p=0.0374; expected counts model no association within the population.

Eij=(row totali)(column totalj)124,χ2=6.573,df=2.

Interpretation and validity

Expected counts interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Expected counts: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 4

Degrees of freedom

Decision

For Degrees of freedom in chi square test of independence, One constructed random sample from a battery-life laboratory trial classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 30, 15]. Test independence for degrees of freedom.

Degrees of freedom result in chi square test of independence: For the independence test, χ2=7.412, df=2, and p=0.0246; expected counts model no association within the population.

Eij=(row totali)(column totalj)126,χ2=7.412,df=2.

Interpretation and validity

Degrees of freedom interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Degrees of freedom: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 5

Chi-square contributions

Decision

For Chi-square contributions in chi square test of independence, One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 27, 15]. Test independence for chi-square contributions.

Chi-square contributions result in chi square test of independence: For the independence test, χ2=6.844, df=2, and p=0.0327; expected counts model no association within the population.

Eij=(row totali)(column totalj)124,χ2=6.844,df=2.

Interpretation and validity

Chi-square contributions interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Chi-square contributions: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 6

Calculator

Decision

For Calculator in chi square test of independence, One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 28, 15]. Test independence for calculator.

Calculator result in chi square test of independence: For the independence test, χ2=5.325, df=2, and p=0.0698; expected counts model no association within the population.

Eij=(row totali)(column totalj)121,χ2=5.325,df=2.

Interpretation and validity

Calculator interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Calculator: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 7

Conclusion

Decision

For Conclusion in chi square test of independence, One constructed random sample from a package-delivery sample classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 29, 15]. Test independence for conclusion.

Conclusion result in chi square test of independence: For the independence test, χ2=6.094, df=2, and p=0.0475; expected counts model no association within the population.

Eij=(row totali)(column totalj)123,χ2=6.094,df=2.

Interpretation and validity

Conclusion interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Conclusion: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.
Step 8

Association

Decision

For Association in chi square test of independence, One constructed random sample from a recycling-behavior survey classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 30, 15]. Test independence for association.

Association result in chi square test of independence: For the independence test, χ2=6.912, df=2, and p=0.0315; expected counts model no association within the population.

Eij=(row totali)(column totalj)125,χ2=6.912,df=2.

Interpretation and validity

Association interpretation for chi square test of independence: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.

Condition evidence for chi square test of independence and Association: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

Procedure error: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Procedure Practice and Full Solutions

Every question in Chi-Square Test of Independence: Complete Guide is newly written from the revised framework and the logic visible in public College Board materials. Constructed numerical settings are identified as instructional scenarios and are never represented as measurements from a real population. No released or secure question wording is reproduced.

Easy Practice

Easy 1: Chi-square contributions

Question P69-Easy-1. One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 27, 15]. Test independence for chi-square contributions.

Worked solution and validity check

Worked solution P69-Easy-1. For the independence test, χ2=5.043, df=2, and p=0.0804; expected counts model no association within the population. Eij=(row totali)(column totalj)120,χ2=5.043,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 2: Calculator

Question P69-Easy-2. One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 28, 15]. Test independence for calculator.

Worked solution and validity check

Worked solution P69-Easy-2. For the independence test, χ2=5.782, df=2, and p=0.0555; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.782,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 3: Conclusion

Question P69-Easy-3. One constructed random sample from a seedling-growth comparison classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 29, 15]. Test independence for conclusion.

Worked solution and validity check

Worked solution P69-Easy-3. For the independence test, χ2=6.573, df=2, and p=0.0374; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.573,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 4: Association

Question P69-Easy-4. One constructed random sample from a website response-time study classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 30, 15]. Test independence for association.

Worked solution and validity check

Worked solution P69-Easy-4. For the independence test, χ2=7.412, df=2, and p=0.0246; expected counts model no association within the population. Eij=(row totali)(column totalj)126,χ2=7.412,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 5: Two-way table

Question P69-Easy-5. One constructed random sample from a manufacturing fill-volume check classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 27, 15]. Test independence for two-way table.

Worked solution and validity check

Worked solution P69-Easy-5. For the independence test, χ2=6.844, df=2, and p=0.0327; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.844,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 6: Hypotheses

Question P69-Easy-6. One constructed random sample from a tutoring-program evaluation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 28, 15]. Test independence for hypotheses.

Worked solution and validity check

Worked solution P69-Easy-6. For the independence test, χ2=5.325, df=2, and p=0.0698; expected counts model no association within the population. Eij=(row totali)(column totalj)121,χ2=5.325,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 7: Expected counts

Question P69-Easy-7. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 29, 15]. Test independence for expected counts.

Worked solution and validity check

Worked solution P69-Easy-7. For the independence test, χ2=6.094, df=2, and p=0.0475; expected counts model no association within the population. Eij=(row totali)(column totalj)123,χ2=6.094,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 8: Degrees of freedom

Question P69-Easy-8. One constructed random sample from a quality-control inspection classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 30, 15]. Test independence for degrees of freedom.

Worked solution and validity check

Worked solution P69-Easy-8. For the independence test, χ2=6.912, df=2, and p=0.0315; expected counts model no association within the population. Eij=(row totali)(column totalj)125,χ2=6.912,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 9: Chi-square contributions

Question P69-Easy-9. One constructed random sample from a quality-control inspection classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 27, 15]. Test independence for chi-square contributions.

Worked solution and validity check

Worked solution P69-Easy-9. For the independence test, χ2=6.385, df=2, and p=0.0411; expected counts model no association within the population. Eij=(row totali)(column totalj)123,χ2=6.385,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 10: Calculator

Question P69-Easy-10. One constructed random sample from a reading-speed investigation classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 28, 15]. Test independence for calculator.

Worked solution and validity check

Worked solution P69-Easy-10. For the independence test, χ2=7.189, df=2, and p=0.0275; expected counts model no association within the population. Eij=(row totali)(column totalj)125,χ2=7.189,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 11: Conclusion

Question P69-Easy-11. One constructed random sample from a school library checkout study classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 29, 15]. Test independence for conclusion.

Worked solution and validity check

Worked solution P69-Easy-11. For the independence test, χ2=5.622, df=2, and p=0.0602; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.622,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 12: Association

Question P69-Easy-12. One constructed random sample from a website response-time study classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 30, 15]. Test independence for association.

Worked solution and validity check

Worked solution P69-Easy-12. For the independence test, χ2=6.418, df=2, and p=0.0404; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.418,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 13: Two-way table

Question P69-Easy-13. One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 27, 15]. Test independence for two-way table.

Worked solution and validity check

Worked solution P69-Easy-13. For the independence test, χ2=5.931, df=2, and p=0.0515; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.931,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 14: Hypotheses

Question P69-Easy-14. One constructed random sample from a battery-life laboratory trial classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 28, 15]. Test independence for hypotheses.

Worked solution and validity check

Worked solution P69-Easy-14. For the independence test, χ2=6.715, df=2, and p=0.0348; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.715,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Easy 15: Expected counts

Question P69-Easy-15. One constructed random sample from a public-parks visitor survey classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 29, 15]. Test independence for expected counts.

Worked solution and validity check

Worked solution P69-Easy-15. For the independence test, χ2=7.546, df=2, and p=0.0230; expected counts model no association within the population. Eij=(row totali)(column totalj)126,χ2=7.546,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough Practice

Tough 1: Association

Question P69-Tough-1. One constructed random sample from a website response-time study classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 27, 15]. Test independence for association.

Worked solution and validity check

Worked solution P69-Tough-1. For the independence test, χ2=5.043, df=2, and p=0.0804; expected counts model no association within the population. Eij=(row totali)(column totalj)120,χ2=5.043,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 2: Two-way table

Question P69-Tough-2. One constructed random sample from a commuter route study classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 28, 15]. Test independence for two-way table.

Worked solution and validity check

Worked solution P69-Tough-2. For the independence test, χ2=5.782, df=2, and p=0.0555; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.782,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 3: Hypotheses

Question P69-Tough-3. One constructed random sample from a campus dining survey classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 29, 15]. Test independence for hypotheses.

Worked solution and validity check

Worked solution P69-Tough-3. For the independence test, χ2=6.573, df=2, and p=0.0374; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.573,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 4: Expected counts

Question P69-Tough-4. One constructed random sample from a commuter route study classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 30, 15]. Test independence for expected counts.

Worked solution and validity check

Worked solution P69-Tough-4. For the independence test, χ2=7.412, df=2, and p=0.0246; expected counts model no association within the population. Eij=(row totali)(column totalj)126,χ2=7.412,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 5: Degrees of freedom

Question P69-Tough-5. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 27, 15]. Test independence for degrees of freedom.

Worked solution and validity check

Worked solution P69-Tough-5. For the independence test, χ2=6.844, df=2, and p=0.0327; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.844,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 6: Chi-square contributions

Question P69-Tough-6. One constructed random sample from a reading-speed investigation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 28, 15]. Test independence for chi-square contributions.

Worked solution and validity check

Worked solution P69-Tough-6. For the independence test, χ2=5.325, df=2, and p=0.0698; expected counts model no association within the population. Eij=(row totali)(column totalj)121,χ2=5.325,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 7: Calculator

Question P69-Tough-7. One constructed random sample from a reading-speed investigation classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 29, 15]. Test independence for calculator.

Worked solution and validity check

Worked solution P69-Tough-7. For the independence test, χ2=6.094, df=2, and p=0.0475; expected counts model no association within the population. Eij=(row totali)(column totalj)123,χ2=6.094,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 8: Conclusion

Question P69-Tough-8. One constructed random sample from a quality-control inspection classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 30, 15]. Test independence for conclusion.

Worked solution and validity check

Worked solution P69-Tough-8. For the independence test, χ2=6.912, df=2, and p=0.0315; expected counts model no association within the population. Eij=(row totali)(column totalj)125,χ2=6.912,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 9: Association

Question P69-Tough-9. One constructed random sample from a classroom memory study classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 27, 15]. Test independence for association.

Worked solution and validity check

Worked solution P69-Tough-9. For the independence test, χ2=6.385, df=2, and p=0.0411; expected counts model no association within the population. Eij=(row totali)(column totalj)123,χ2=6.385,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 10: Two-way table

Question P69-Tough-10. One constructed random sample from a tutoring-program evaluation classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 28, 15]. Test independence for two-way table.

Worked solution and validity check

Worked solution P69-Tough-10. For the independence test, χ2=7.189, df=2, and p=0.0275; expected counts model no association within the population. Eij=(row totali)(column totalj)125,χ2=7.189,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 11: Hypotheses

Question P69-Tough-11. One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 29, 15]. Test independence for hypotheses.

Worked solution and validity check

Worked solution P69-Tough-11. For the independence test, χ2=5.622, df=2, and p=0.0602; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.622,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 12: Expected counts

Question P69-Tough-12. One constructed random sample from a quality-control inspection classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 30, 15]. Test independence for expected counts.

Worked solution and validity check

Worked solution P69-Tough-12. For the independence test, χ2=6.418, df=2, and p=0.0404; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.418,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 13: Degrees of freedom

Question P69-Tough-13. One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 27, 15]. Test independence for degrees of freedom.

Worked solution and validity check

Worked solution P69-Tough-13. For the independence test, χ2=5.931, df=2, and p=0.0515; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.931,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 14: Chi-square contributions

Question P69-Tough-14. One constructed random sample from a classroom memory study classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 28, 15]. Test independence for chi-square contributions.

Worked solution and validity check

Worked solution P69-Tough-14. For the independence test, χ2=6.715, df=2, and p=0.0348; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.715,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Tough 15: Calculator

Question P69-Tough-15. One constructed random sample from a manufacturing fill-volume check classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 29, 15]. Test independence for calculator.

Worked solution and validity check

Worked solution P69-Tough-15. For the independence test, χ2=7.546, df=2, and p=0.0230; expected counts model no association within the population. Eij=(row totali)(column totalj)126,χ2=7.546,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest Practice

Toughest 1: Two-way table

Question P69-Toughest-1. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 27, 15]. Test independence for two-way table.

Worked solution and validity check

Worked solution P69-Toughest-1. For the independence test, χ2=5.043, df=2, and p=0.0804; expected counts model no association within the population. Eij=(row totali)(column totalj)120,χ2=5.043,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 2: Hypotheses

Question P69-Toughest-2. One constructed random sample from a greenhouse germination experiment classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 28, 15]. Test independence for hypotheses.

Worked solution and validity check

Worked solution P69-Toughest-2. For the independence test, χ2=5.782, df=2, and p=0.0555; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.782,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 3: Expected counts

Question P69-Toughest-3. One constructed random sample from a reading-speed investigation classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 29, 15]. Test independence for expected counts.

Worked solution and validity check

Worked solution P69-Toughest-3. For the independence test, χ2=6.573, df=2, and p=0.0374; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.573,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 4: Degrees of freedom

Question P69-Toughest-4. One constructed random sample from a seedling-growth comparison classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 30, 15]. Test independence for degrees of freedom.

Worked solution and validity check

Worked solution P69-Toughest-4. For the independence test, χ2=7.412, df=2, and p=0.0246; expected counts model no association within the population. Eij=(row totali)(column totalj)126,χ2=7.412,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 5: Chi-square contributions

Question P69-Toughest-5. One constructed random sample from a quality-control inspection classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 27, 15]. Test independence for chi-square contributions.

Worked solution and validity check

Worked solution P69-Toughest-5. For the independence test, χ2=6.844, df=2, and p=0.0327; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.844,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 6: Calculator

Question P69-Toughest-6. One constructed random sample from a tutoring-program evaluation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 28, 15]. Test independence for calculator.

Worked solution and validity check

Worked solution P69-Toughest-6. For the independence test, χ2=5.325, df=2, and p=0.0698; expected counts model no association within the population. Eij=(row totali)(column totalj)121,χ2=5.325,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 7: Conclusion

Question P69-Toughest-7. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 29, 15]. Test independence for conclusion.

Worked solution and validity check

Worked solution P69-Toughest-7. For the independence test, χ2=6.094, df=2, and p=0.0475; expected counts model no association within the population. Eij=(row totali)(column totalj)123,χ2=6.094,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 8: Association

Question P69-Toughest-8. One constructed random sample from a website response-time study classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 30, 15]. Test independence for association.

Worked solution and validity check

Worked solution P69-Toughest-8. For the independence test, χ2=6.912, df=2, and p=0.0315; expected counts model no association within the population. Eij=(row totali)(column totalj)125,χ2=6.912,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 9: Two-way table

Question P69-Toughest-9. One constructed random sample from a water-filtration experiment classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 27, 15]. Test independence for two-way table.

Worked solution and validity check

Worked solution P69-Toughest-9. For the independence test, χ2=6.385, df=2, and p=0.0411; expected counts model no association within the population. Eij=(row totali)(column totalj)123,χ2=6.385,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 10: Hypotheses

Question P69-Toughest-10. One constructed random sample from an online-course completion sample classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 28, 15]. Test independence for hypotheses.

Worked solution and validity check

Worked solution P69-Toughest-10. For the independence test, χ2=7.189, df=2, and p=0.0275; expected counts model no association within the population. Eij=(row totali)(column totalj)125,χ2=7.189,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 11: Expected counts

Question P69-Toughest-11. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [30, 20, 10] and [18, 29, 15]. Test independence for expected counts.

Worked solution and validity check

Worked solution P69-Toughest-11. For the independence test, χ2=5.622, df=2, and p=0.0602; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.622,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 12: Degrees of freedom

Question P69-Toughest-12. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [31, 20, 10] and [18, 30, 15]. Test independence for degrees of freedom.

Worked solution and validity check

Worked solution P69-Toughest-12. For the independence test, χ2=6.418, df=2, and p=0.0404; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.418,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 13: Chi-square contributions

Question P69-Toughest-13. One constructed random sample from a manufacturing fill-volume check classifies each unit by two categorical variables. The observed rows are [32, 20, 10] and [18, 27, 15]. Test independence for chi-square contributions.

Worked solution and validity check

Worked solution P69-Toughest-13. For the independence test, χ2=5.931, df=2, and p=0.0515; expected counts model no association within the population. Eij=(row totali)(column totalj)122,χ2=5.931,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 14: Calculator

Question P69-Toughest-14. One constructed random sample from a public-parks visitor survey classifies each unit by two categorical variables. The observed rows are [33, 20, 10] and [18, 28, 15]. Test independence for calculator.

Worked solution and validity check

Worked solution P69-Toughest-14. For the independence test, χ2=6.715, df=2, and p=0.0348; expected counts model no association within the population. Eij=(row totali)(column totalj)124,χ2=6.715,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Toughest 15: Conclusion

Question P69-Toughest-15. One constructed random sample from a city bus arrival investigation classifies each unit by two categorical variables. The observed rows are [34, 20, 10] and [18, 29, 15]. Test independence for conclusion.

Worked solution and validity check

Worked solution P69-Toughest-15. For the independence test, χ2=7.546, df=2, and p=0.0230; expected counts model no association within the population. Eij=(row totali)(column totalj)126,χ2=7.546,df=2. Interpretation: A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. Validity: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation. Error to reject: The independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

AP Response and Publication Checklist

Audit pointRequired evidence for chi square test of independence
ScopeThe conclusion concerns association within one population.
Method or sourceA chi-square test of independence uses one population classified by two categorical variables and concludes about association between those variables.
CalculationEij=(row totali)(column totalj)120,χ2=5.043,df=2.
InterpretationA small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design.
ValidityOne probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.
CorrectionThe independence conclusion concerns association between two variables in one population, not equality of several separately sampled populations.

Frequently Asked Questions

How does two-way table work in chi square test of independence?

Answer for chi square test of independence and Two-way table. For the independence test, χ2=5.043, df=2, and p=0.0804; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. The required validity evidence is: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

How does hypotheses work in chi square test of independence?

Answer for chi square test of independence and Hypotheses. For the independence test, χ2=5.782, df=2, and p=0.0555; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. The required validity evidence is: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

How does expected counts work in chi square test of independence?

Answer for chi square test of independence and Expected counts. For the independence test, χ2=6.573, df=2, and p=0.0374; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. The required validity evidence is: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

How does degrees of freedom work in chi square test of independence?

Answer for chi square test of independence and Degrees of freedom. For the independence test, χ2=7.412, df=2, and p=0.0246; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. The required validity evidence is: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

How does chi-square contributions work in chi square test of independence?

Answer for chi square test of independence and Chi-square contributions. For the independence test, χ2=6.844, df=2, and p=0.0327; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. The required validity evidence is: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

How does calculator work in chi square test of independence?

Answer for chi square test of independence and Calculator. For the independence test, χ2=5.325, df=2, and p=0.0698; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. The required validity evidence is: One probability sample supplies independent observational units; every unit contributes to exactly one cell, and expected counts support the approximation.

How does chi square test independent connect to Chi-Square Test Of Independence?

chi square test independent within chi square test of independence. For the independence test, χ2=5.043, df=2, and p=0.0804; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Two-way table, the controlling scope is: The conclusion concerns association within one population.

How does chi-square test of independence connect to Chi-Square Test Of Independence?

chi-square test of independence within chi square test of independence. For the independence test, χ2=5.782, df=2, and p=0.0555; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Hypotheses, the controlling scope is: The conclusion concerns association within one population.

How does chi square test for independence connect to Chi-Square Test Of Independence?

chi square test for independence within chi square test of independence. For the independence test, χ2=6.573, df=2, and p=0.0374; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Expected counts, the controlling scope is: The conclusion concerns association within one population.

How does chi squared test of independence connect to Chi-Square Test Of Independence?

chi squared test of independence within chi square test of independence. For the independence test, χ2=7.412, df=2, and p=0.0246; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Degrees of freedom, the controlling scope is: The conclusion concerns association within one population.

How does chi square independence test connect to Chi-Square Test Of Independence?

chi square independence test within chi square test of independence. For the independence test, χ2=6.844, df=2, and p=0.0327; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Chi-square contributions, the controlling scope is: The conclusion concerns association within one population.

How does chi-square test for independence connect to Chi-Square Test Of Independence?

chi-square test for independence within chi square test of independence. For the independence test, χ2=5.325, df=2, and p=0.0698; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Calculator, the controlling scope is: The conclusion concerns association within one population.

How does independent chi square test connect to Chi-Square Test Of Independence?

independent chi square test within chi square test of independence. For the independence test, χ2=6.094, df=2, and p=0.0475; expected counts model no association within the population. A small p-value gives evidence that the two categorical variables are associated in the population represented by the one-sample design. For Conclusion, the controlling scope is: The conclusion concerns association within one population.

Sources

Administrative and curricular statements in Chi-Square Test of Independence: Complete Guide were checked on July 18, 2026. The linked College Board pages control any later policy change; all instructional datasets in original questions are explicitly constructed rather than attributed to a real study.

Chi-Square Test Of Independence Conclusion

A chi-square test of independence uses one population classified by two categorical variables and concludes about association between those variables. Mastery of chi square test of independence therefore requires the exact evidence, mathematics, interpretation, and scope developed in this guide, while preserving this boundary: The conclusion concerns association within one population.

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Engr. Muhammad Yar Saqib

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